Exercice 977 *
1 avril 2021 11:57
— Par Emmanuel Vieillard-Baron
Alain Soyeur
François Capaces
Résoudre dans
\(\mathbb{R}^3\) les systèmes :
\(\left\{ \begin{aligned} x&-y&+z&=&1\cr
&3y&-z&=&2\cr
& &2z&=&8 \end{aligned}\right.\)
\(\left\{ \begin{aligned} x&-y&+2z&=&1\cr
2x&-3y&+z&=&4\cr
x&-3y&-4z&=&5 \end{aligned}\right.\)
\(\left\{ \begin{aligned} x&+2y&+3z&=&1\cr
-x&-3y&+5z&=&2\cr
x&+y&+z&=&-1 \end{aligned}\right.\)
\(\left\{ \begin{aligned} &y&+3z&=&0\cr
x&+2y&+6z&=&2\cr
7x&+3y&+9z&=&14 \end{aligned}\right.\)
\(\left\{ \begin{aligned} x&+2y&+z&=&2\cr
2x&+y&+z&=&-1\cr
x&-3y&+2z&=&-1 \end{aligned}\right.\)
\(\left\{ \begin{aligned} 2x&-y&+3z&=&1\cr
x&+y&-z&=&2\cr
x&-2y&+4z&=&1 \end{aligned}\right.\)
\(\left\{ \begin{aligned} 2x&-y&+3z&=&0\cr
x&+y&+2z&=&0 \end{aligned}\right.\)
\(\left\{ \begin{aligned} x&+y&-z&=&1\cr
2x&+2y&-2z&=&2\cr
-x&-y&+z&=&-1 \end{aligned}\right.\)